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x^2+5x-25/4=0
We multiply all the terms by the denominator
x^2*4+5x*4-25=0
Wy multiply elements
4x^2+20x-25=0
a = 4; b = 20; c = -25;
Δ = b2-4ac
Δ = 202-4·4·(-25)
Δ = 800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{800}=\sqrt{400*2}=\sqrt{400}*\sqrt{2}=20\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-20\sqrt{2}}{2*4}=\frac{-20-20\sqrt{2}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+20\sqrt{2}}{2*4}=\frac{-20+20\sqrt{2}}{8} $
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